TypeExtensionsGetFriendlyClassName Method

Gets the friendly class name of the provided type, trimming generic parameters.

Definition

Namespace: Gemstone.TypeExtensions
Assembly: Gemstone.Common (in Gemstone.Common.dll) Version: 1.0.181 -- Release Build+97279656b5a55675063a4190481e67c4f9809501

C#View Source Request Example

public static string GetFriendlyClassName(
	this Type? type
)

VBView Source Request Example

<ExtensionAttribute>
Public Shared Function GetFriendlyClassName ( 
	type As Type
) As String

C++View Source Request Example

public:
[ExtensionAttribute]
static String^ GetFriendlyClassName(
	Type^ type
)

JavaScriptView Source Request Example

Gemstone.TypeExtensions.TypeExtensions.GetFriendlyClassName = function(type);

Parameters

type Type: Type to get friendly class name for.

Return Value

String
Friendly class name of the provided type, or Empty if type is null.

Usage Note

In Visual Basic and C#, you can call this method as an instance method on any object of type Type. When you use instance method syntax to call this method, omit the first parameter. For more information, see Extension Methods (Visual Basic) or Extension Methods (C# Programming Guide).

TypeExtensionsGetFriendlyClassName Method

Definition

Parameters

Return Value

Usage Note

See Also

Reference