RandomNumberExtensionsToNormalDistribution Method

Linq extension function used to Transform an enumerable of UniformRandomNumber to an enumerable of NormalRandomNumber

Definition

Namespace: Gemstone.Numeric.Random
Assembly: Gemstone.Numeric (in Gemstone.Numeric.dll) Version: 1.0.170 -- Release Build+bbba6fd4a26a340bfc358a3686e9fa5973d54075

C#View Source Request Example

public static IEnumerable<NormalRandomNumber> ToNormalDistribution(
	this IEnumerable<UniformRandomNumber> uniforms,
	double mean = 0,
	double variance = 1
)

VBView Source Request Example

<ExtensionAttribute>
Public Shared Function ToNormalDistribution ( 
	uniforms As IEnumerable(Of UniformRandomNumber),
	Optional mean As Double = 0,
	Optional variance As Double = 1
) As IEnumerable(Of NormalRandomNumber)

C++View Source Request Example

public:
[ExtensionAttribute]
static IEnumerable<NormalRandomNumber^>^ ToNormalDistribution(
	IEnumerable<UniformRandomNumber^>^ uniforms, 
	double mean = 0, 
	double variance = 1
)

JavaScriptView Source Request Example

Gemstone.Numeric.Random.RandomNumberExtensions.ToNormalDistribution = function(uniforms, mean, variance);

Parameters

uniforms IEnumerableUniformRandomNumber: enumerable of UniformRandomNumber
mean Double (Optional): Mean of normal distribution
variance Double (Optional): Variance of normal distribution

Return Value

IEnumerableNormalRandomNumber
IEnumerableT

Usage Note

In Visual Basic and C#, you can call this method as an instance method on any object of type IEnumerableUniformRandomNumber. When you use instance method syntax to call this method, omit the first parameter. For more information, see Extension Methods (Visual Basic) or Extension Methods (C# Programming Guide).

RandomNumberExtensionsToNormalDistribution Method

Definition

Parameters

Return Value

Usage Note

See Also

Reference